Optimal. Leaf size=119 \[ \frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \left (-\tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
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Rubi [A] time = 0.114609, antiderivative size = 119, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {850, 811, 844, 217, 203, 266, 63, 208} \[ \frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \left (-\tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
Antiderivative was successfully verified.
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Rule 850
Rule 811
Rule 844
Rule 217
Rule 203
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\left (d^2-e^2 x^2\right )^{5/2}}{x^5 (d+e x)} \, dx &=\int \frac{(d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{x^5} \, dx\\ &=-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}-\frac{\int \frac{\left (6 d^3 e^2-8 d^2 e^3 x\right ) \sqrt{d^2-e^2 x^2}}{x^3} \, dx}{8 d^2}\\ &=\frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{\int \frac{12 d^5 e^4-32 d^4 e^5 x}{x \sqrt{d^2-e^2 x^2}} \, dx}{32 d^4}\\ &=\frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{1}{8} \left (3 d e^4\right ) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx-e^5 \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx\\ &=\frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{1}{16} \left (3 d e^4\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )-e^5 \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )\\ &=\frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}-e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{1}{8} \left (3 d e^2\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )\\ &=\frac{e^2 (3 d-8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d-4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}-e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )\\ \end{align*}
Mathematica [A] time = 0.203241, size = 111, normalized size = 0.93 \[ \frac{1}{24} \left (\frac{\sqrt{d^2-e^2 x^2} \left (8 d^2 e x-6 d^3+15 d e^2 x^2-32 e^3 x^3\right )}{x^4}-9 e^4 \log \left (\sqrt{d^2-e^2 x^2}+d\right )-24 e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )+9 e^4 \log (x)\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.081, size = 463, normalized size = 3.9 \begin{align*}{\frac{e}{3\,{d}^{4}{x}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{{e}^{3}}{3\,{d}^{6}x} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{{e}^{5}x}{3\,{d}^{6}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}-{\frac{5\,{e}^{5}x}{12\,{d}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}-{\frac{3\,d{e}^{4}}{8}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}}-{\frac{{e}^{2}}{8\,{d}^{5}{x}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{{e}^{5}x}{4\,{d}^{4}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}}}-{\frac{3\,{e}^{5}x}{8\,{d}^{2}}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}-{\frac{5\,{e}^{5}}{8}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{1}{4\,{d}^{3}{x}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}-{\frac{{e}^{4}}{5\,{d}^{5}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{5}{2}}}}-{\frac{3\,{e}^{5}}{8}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}+{\frac{3\,{e}^{4}}{40\,{d}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{{e}^{4}}{8\,{d}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{3\,{e}^{4}}{8\,d}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{5\,{e}^{5}x}{8\,{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.63645, size = 247, normalized size = 2.08 \begin{align*} \frac{48 \, e^{4} x^{4} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) + 9 \, e^{4} x^{4} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) -{\left (32 \, e^{3} x^{3} - 15 \, d e^{2} x^{2} - 8 \, d^{2} e x + 6 \, d^{3}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{24 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 15.7384, size = 552, normalized size = 4.64 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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